test.txt (1597B)
1 1)a)i) in book 2 1)a)ii) in book 3 1)a)iii) in book 4 5 1)b) in book 6 7 1)c)i) in book 8 1)c)ii) in book 9 1)c)iii) in book 10 1)c)iv) in book 11 12 2)a)i) forward 13 2)a)ii) reverse 14 2)a)iii) reverse 15 2)a)iv) forward 16 2)b) in book 17 2)c)i) in book 18 2)c)ii) in book 19 2)c)iii) in book 20 2)c)iv) in book 21 22 3)a) in book 23 3)b) in book 24 25 4)a)i) in book 26 4)a)ii) I believe it would be close to 0V as the input of 100Hz is very low, and this is a high pass filter meaning only high frequency signals should pass through 27 4)b) They can have a gain greater than 1, they can be stricter (have a sharper cut off, higher Q factor), than a passive filter 28 4)c)i) in book 29 4)c)ii) in book 30 31 5) 32 - the diode must be between the mesurment middle point and point C, this is because there is 0 current flowing when C is connected to 9V 33 - you can also tell this because current flows from A-B and B-A just fine 34 - there is a resistor going from A to the mid point, and from B to the mid point 35 - the resistor from A to the mid point must be 100 ohms, this is because there R = V/I, we can use the result from A-C (resistor through diode) to tell that V = 9 - 0.7 and the table to tell us that I = 0.083 which gives us 100 ohms 36 - the resistor from B to the mid point must be 100 ohms, this is because there R = V/I, we can use the result from B-C (resistor through diode) to tell that V = 9 - 0.7 and the table to tell us that I = 0.0415 which gives us 200 ohms 37 - this can be confirmed by the fact that using the table values fro A-B or B-A, we can say 9/0.3 to get the resistance or Ra + Rb which is 300 ohms, thus confirming our result from before 38 39 40 41 42 43 44